On Kreatinins. 



523 



Required for 

 Found in C 4 H 7 N 3 0.2H 2 

 100 parts. (C 4 H n N 3 03). 



Carbon 3231 32*21 



Hydrogen 7'16 7'30 



The ultimate analysis of the efflorescent kreatinin after efflorescence 

 proves that the composition of the effloresced substance is identical 

 with that of the anhydrous tabular kreatinin from urinary kreatin. 



Ultimate Analysis of Effloresced Kreatinin from Kreatin of Urine 

 and of Tabular Kreatinin from the same source. 



Description of 

 substance. 



"Weight of 

 substance 

 in grams. 



Weight of 

 hydrogen 

 found. 



Weight of 

 carbon 

 found. 



H in 

 100 

 parts. 



C in 

 100 

 parts. 



Effloresced kreatinin 













from kreatin of 















0-215 



-0137 



-09136 



6*404 



42-49 



Tabular kreatinin 













from kreatin of 















0-312 



0-0195 



0-1342 



6-26 



43-01 



Tabular kreatinin 













from kreatin of 















1515 



-oioo 



-0641 



660 



42-47 



Description of substance. 



Effloresced kreatinin from 

 urinary kreatin 



Tabular kreatinin from 

 urinary kreatin 



Weight of 

 substance 

 in giams. 



0*154 

 -1505 



Vol. of 

 nitrogen at 

 0° C. and 

 760 mm. 



c.c. 

 45 -574 

 44-53 



Weight of 

 nitrogen 

 in grams. 



Nitrogen 

 in 100 

 parts. 



0-057171 

 -055862 



37-123 

 37-117 



These results agree well with the formula C 4 H 7 jN~ 3 0, as shown by 

 the following table : — 



Oxygen (by difference) . . 



Found in tabular 

 kreatinin from 

 urinary kreatin. 



In effloresced 

 kreatinin from 

 same source. 



Required for 

 C 4 H 7 N 3 in 

 100 parts. 



Mean. 



SS} «<» 



37 -117 

 13 -793 



42-49 



6-404 



37 -123 

 (differ.) 13 -983 



42 -478 



6-194 



37-168 

 14-160 



100 -ooo 



100 -ooo 



100 -ooo 



