66 Mr. J. M. Heppel on the Theory of Continuous Beams. 

 and central deflection from equation (21), 



/ 7 * 1 . 2 / 11 1 ,1 



18 



, / 5 * 5 . . 2 / 5 .47 5 \\ 

 + e3 (-I^ -^^ +a2 (^ + lV^ + lli^)) 



\144 



36 



If we put b = 2a, c= 3a, d=4a, l=5a, 



Y=a 



+ 



13 

 150* 



2/149 



a w 



V150 



+ e 2 



31 

 150 



91 , 



300^ + 



13 

 60 



i«3 + 



13 

 100' 



123 



200^ 2i " 



31 

 60 



/<3 + 



31 

 100 



19 , 



13 



24 



^3 + 



37 

 100 



7 , 



7 



30 



/*8 + 



161 



600 



1 , 



1 



30 





7 

 150 



, 31 

 ^ + 300^ 



31 



300 



and central deflection from equation (23), 



+ 6, 

 + € 



( 13^ 1 2/ 7 ,7 ,1 , 1 ,1 

 1 V~ 6O^~^ 02+a lW Atl+ ¥MT2 ft f 20^ + "60 ^ 



(- 



3^ 

 60 



30^ + " (j757^i + oln^+ Toft+ oST^ 



•(-si*" 



120 

 9 



32 



,27 , 469 , 27 , 9 



31 



"60" 



32 



o/7 ,7 ,7 ,161 ,31 

 VW 1 " 1 " T^3+ 5^4+ Y^Ht 



12 



240' 



120 



/ 1 13 . 2 / 1 , 1 , 1 , 7 7 



As an example of the application of the foregoing method to the 

 purposes of calculation, let the case of the Britannia Bridge be taken, and 

 let the large span be supposed to be divided into five, and the small span 

 into three equal parts, and let the moments of inertia of the sections and 

 loads per unit of length be supposed constant within each part and equal 

 to their mean values. 



_1 2 



"A V a' A a b c d A 



