-378- 



Mineralogie. 



Im Ganzen wurden 95 Formen an den Krystallen beobachtet, darunter 

 fünf nur von Baumhauer an zwei Krystallen des Museums in Freiburg 

 i. Schweiz (laut briefl. Mittheilung an den Verf.). 



a = (100) ooPoo -j- -|h = (503) fPoo 



b = (010) ooPoo + f h = (805) ^Poo 



c = (001) 0P 4-fn = (302) |Poc 



-30h = (30.0.1) - 30Poo +h = (10T) Poo 



- Vh = (25 . . 2) - y.3Poo + |g = (304) fPoo 



- V 3 h = (13.0.2)- V 3 Poo + |g = (203) fPoo 

 -5h = (501) -5Poo +ig = (102) iPoo 



: (205) fPoo 



: (308) f-PoO 

 : (103) IPOO 



(104) iPoo 

 (2.0. 13) -^Pco 



(109) |Poo 

 (1 . . 12) T LPoo 

 (140) ooP4 

 (120) ooP2 

 (340) ooPf 



(110) oop Ö 



(980) ooPf 

 (320) ooPf 

 (950) ooPf 

 (210) ooP2 

 (17 .'8.0) ooPy 

 (520) ooPf 

 (830) ooP| 

 (310) ooP3 

 (10.3.0) ooPlo 

 (11.3.0) ooPV 



— |h = (902) — |Poo 



4- 



\ 5» 



— 4h = (401) — 4Poo 



4- l-ff 



— 8» 



— |h'= (702) — |Poo 



-4-io- 



— 3& 



— 3h = (301) — 3Poo 





- yh = (13.0.5) — MPoo 



-4- - 2 -2' 

 T 13b 



— fh = (502) — fPoo° 



4- -iff 

 r 9& 



- = (13.0.6) — L3f>oo 



4- JL ff 

 1 1 2& 



— 2h = (201) — 2Poo 



4r 



— yh = (13 . . 7) — V 3 Poo 



2r 



- f h = (302) - |Poo ' 



|r 



— ih = (705) — |Poo 



r 



— fh = (403) — |Poo 



fs 



-|h = (706) -|Poo 



fs 



- |f h (13 . . 12) — if Poo 



fs 



— h = (101) — Poo 



2s 



-Ig = (506) - f Poo 



¥ s 



-±g = (405) -|Poo 





- = (304) - f Poo 





- |g = (508) - fPoo 



3s 



- lg = (102) - |Poo 



3 & 



- |g = (205) - f Poo 



3 & 



- ig = (103) - iPoo 



Vs 



-ig = (104) -|Poo 



-2q 



-ig == (106) -iPoo 



— P 



- ig = (107) - iPoo 



+ 2q 



(11.2. 0) ooPy 

 (121) — 2P2 

 (111) -P 

 (12T) 2P2 



- ig = (109) - iPoo + p = (Hl) p 



4- 8h = (801) 8Pcx> . + u = (211) 2 P2 



+ yh = (11^0 . 2) VPoo — 4x == (342) - 2Pf 



4- 5h = (501) 5Poo _ 2x = (322) - fPf 



+ 4h = (401) 4P oo 4- 2x = (322) + f Pf 



4- 3h = (301) 3Poo — In = (142) - 2P4 



+ fh = (502) fPoo — 2n = (122) — P2 



4- V h - (11 -0.5) tfPoo 4-4n = (142) + 2P4 



+ 2h = (201) 2Poo 4- 2n = (122) + P2 



+ V 3 h = (13 . . 7) V 3 ?oo -2y = (522) - fPf 



+ ih = (704) |Poo _}_ 2y = (522) + f Pf 



