2(3 



ANIMAL MECHANICS. 



but 



(w + a) x = o l^w + ^j, 



e = tot 



Hence we find 



Total work = wa + t. (?) 



The following experiments were made upon the unloaded 

 arms — 



No. i.— -Myself, 

 a - 22 inches. w « o. 



a* = 7.5 lbs. t = 420 sees. 



Total work in ft. lbs. = 2887.5 co. 



No. 2.— Dr. A. W. Foot 

 a = 24 inches. w = o. 



# = 7 lbs. £ = 480 sees. » 



Total work in ft. lbs. = 3360 to. 



No. 3. — Captain John Haughton, R. A. 

 a = 22 inches. w = o. 



a = 5 lbs. 14 oz. t = 720 sees. 



Total work in ft. lbs. = 3877.5 u>. 



No. 4.— Mr. M. II. Ormsby. 

 a = 24 inches. w = o. 



a = 6.5 lbs. £ = 390 sees. 



Total work in ft. lbs. = 2535 a». 



* The approximate weight of the arm may be found by weighing it in a 

 balance, whose scale is on a level with the centre of the glenoid cavity, and 

 treating it as a lever, so that the weight of the arm shall be to the weight that 

 supports any point of the arm inversely as the distances of the centre of gravity 

 and of that uoint from the centre of the glenoid cavity. 



