6 



C. V. ],. Charlipr 



Let US first consider a couerete example. Suppose a number of objects to be 

 distributed according to the following correlation table: 



Absolute Diameter 





0.5 



0.6 



0.7 



0.8 



0.9 



1.0 



1.1 



1.2 



1.3 



1.4 



1.5 



12 

 11 



— 



— 



— 





6 



5 

 6 



6 





— 



— 



— 



1 f\ 



LU 



9 









7 



7 



7 

 t 



7 



7 









8 





9 



8 

 9 



8 

 9 



8 

 9 



8 

 9 



8 

 9 



8 

 9 



8 

 9 



9 





7 



10 



10 



10 



10 



10 



10 



10 



10 



10 



10 



10 



6 





9 



9 



9 



9 



9 



9 



9 



9 



9 





5 

 4 







8 



8 

 7 



8 

 7 



8 

 7 



8 

 7 



8 

 7 



8 







a 



2 











6 



6 

 5 



6 











The mean diameter is here supposed to be the same at all distances (= l.o). 

 The mean distance of all objects is 7 and the objects are symmetrically distributed 

 al)out this mean distance. 



Dividing the absolute diameter by the distance we get the apparent diameter. 

 We thus obtain a correlation table between the apparent diameter and the distance. 

 In the present case this correlation table takes the following form: 



Apparent Diameter 





OlO 



(l.lo 





().'25 



0.30 



0.:i5 



()4Ü 



0.45 



0.50 



12 



5 



















11 



18 



















10 



35 



















9 



40 



Ui 

















8 



45 



31 



9 















7 



45 



40 



30 















6 



18 



27 



31 















5 





IG 



24 















4 







14 



7 



14 











3 











6 



12 









2 



















5 



Sum 



206 



130 



108 



7 



20 



12 







5 



Mean 



8.7 



7.0 



6.0 



4.0 



3.7 



3.5 







2.0 



