TJie Isfcglect of Chcmistr/j hij Practical Farmers. 



435 



79.0 X 100 = 7000, which -f- 80 (100 quarts of water; = 

 98.75— the amount of organic matter in 100 parts of dry 

 substance. 



1.0 X 100 = 100, which 4- 80 (100 quarts of water) = 

 1.25 — the amount of ash in 100 parts of dry substance. 



In the second substance we have — 



88.9 X 100 - 8S90, which 4- 90 (100 quarts of water) = 

 98.77 — as the quantity of organic mater in 100 parts of 

 dry substance. 



1.1 X 100 = 110, which ~ 90 (100 quarts of water) - 

 1.23 — the amount of ash in 100 parts of dry matter. 



Here we see that these two specimens are almost identical in 

 their composition, although the impression that would be left by 

 a cursory examination would lead one to suppose that they greatly 

 differed in their organic matter. 



Had I made a greater difference in the amount of water con- 

 tained by each, the effect would have been still more striking. 



The following example will show the means afforded by Form 

 2, for facilitating calculations by means of decimals. 



Example 4. — Suppose the quantity of lime contained in 100 lbs. 

 of oat straw to be G.4S lbs. (vide analyses); required the quantity 

 contained in 1750 lbs. 



Here all we have to do is to multiply — 



1750 by 0.48, and divide by 100 ; or, in other words, 

 17.5 X 0.48 = 8.4, gives the amount required. 



These examples are, I think, sufficient to show the object of and 

 method of using Parts 1 and 2 of these tables. As regards Parts 

 3 and 4, the method of calculating them is so obvious as scarcely 

 to require an illustration, the rule being to multiply the quantities 

 contained in 100 parts of the specimen in its natural state of 

 dryness, by 2240, the number of pounds in a ton, and divide the 

 amount by J 00, which operation is performed at once by multi- 

 plying by 22.4. This gives the number of pounds weight of anv 

 ingredient that is contamed in one ton of the substance : the only 

 difference, when the weight is required in the produce of 1 acre, 

 is, that we multiply by the number of pounds contained in that 

 produce, instead of the number in 1 ton, and divide by 100, as 

 before. The following example will suffice to show the method 

 of using these two forms : — 



Example to Form 3. — Required the quantity of azotised 

 organic matter contained in 4 tons of beans. By referring to 



