Haughton — Notes on Newtonian Chemistry. ' 643 
I have shown that the value of wi must be negative, and assuming 
1 
m 
we transform equation (7) into the following : — 
n^fi^-{2m+l)l3^-(3-m-'] ±{/3+l)m^i:=0. (7)' 
As is a very large number compared with 13, ^, and m, this 
©quation is nearly equivalent to 
. )83_ (2m+ I)y82_y8_^3 = 0. (8) 
In this equation /3 is the atomic weight of one of the four elements 
ainder consideration, and m is the ratio of its molecular periodic time 
to the molecular periodic time of hydrogen; and a relation is thus 
established between y8 and m by which, if either be given, the other 
can be calculated. 
If we assume the following values for the ratio of the periodic 
ifcimes of the four elements to that of hydrogen, we can readily calculate 
from equation (8) the values of the atomic weights. 
Ratio op 
Atomic Weight. 
DiFF. 
Periodic 
Times. 
Calculated. 
Observed. 
Hydrogen,. . 
1 
1-00 
1-00 
± 0-00 
Fluorine, . . 
9 
19-27 
19-00 
+ 0-27 
Chlorine, . . 
17 
35-25 
35-50 
- 0-25 
Eromine, . . 
39 
79-25 
80-00 
- 0-75 
Iodine, . . 
63 
127-25 
127-00 
+ 0-25 
Chemists must decide whether these differences are or are not 
greater than they can allow in the atomic weights of the four elements 
in question. 
In the preceding investigations I have used one hypothesis only, 
viz. that the atoms obey the same law of attraction as the heavenly 
