EXAMPLES TO THE SECOND SERIES. 
XXV 
To find by the Table of Constants, J^o. 2, and the Second Series of 
Tables, the Scantlings of any Species of Timber sufficient to carry 
a weight, which shall be any given -portion of the breaking weight. 
Weight uniformly loaded. 
The breaking weight in cwts, multiplied by the value of c in Col. II. 
p. 50, gives the tabular weight in the Second Series of Tables ; and the 
scantling opposite thereto, or to the next greater weight, is one of the 
scantlings required. 
Example 10.— Required the Scantlings of English Oak 12 feet long, 
sufficient to carry 80 cwts. uniformly loaded ; the breaking weight to 
be 10 times that weight, or 10 X 80 = 800 cwts. uniformly loaded. 
By Col. II. p. 50, for English Oak; c = -1176. 
800 X -1176 = 94-08 cwts. ; the tabular weight. 
By the Second Series of Tables, the following are the scantlings 
and weights for 12 feet long : — 
Oak Scantlings. 
Tabular Weights. 
Notes. 
Table IX, ... 
9 X 14 
94-50 cwts. 
// X. ... 
10 X lU 
95-83 « 
91'66 ..100"00 : g^.g"3 
2 
" " ... 
mx \0i 
96-46 " 
87-50 X 1-1025 = 96-46 
" XI. ... 
11 X 9i 
95-79 » 
90-75 . 100-83 
" XII.... 
12 X 8 
96-00 " 
" " ... 
12^ X 7i 
97-65 » 
90 X 1-085 = 97-65 
To find the deflection of English Oak 12 feet long 12X8, uniformly 
loaded with -j?^th of the breaking weight. 
By Table II. p. 129, the deflection of Red Pine 12 inches deep and 
12 feet long, uniformly loaded with ^th of the breaking weight, is 
By Col. VI. p. 50, for English Oak ; c = 1-684. 
1-684 X -1576 = -265 of an inch; the deflection required. 
Example 1 1.— Required the Joists and Beams for a Warehouse Floor, 
upon the following data : — 
Data for the Joists. 
Joists 8 feet long clear bearing, and 15 inches apart from middle to 
middle. 
