124  CH.  M.  SCHOLS.  LE  CALCUL  DE  LA  DISTANCE  ET  DEL’AZIMUT 
=57°  l = 1°22'  6", 03270  = 
<p,  = 56°13'49», 02186 
= 56°36'54^51093  =z  4600", 97814  = 
: 4926",03270 
2770",97814 
log  X = 3,6924972.9  =a 
log  [IJ 
= 4,9298 
log  sin  =9,9216830.0  =6 
2(ï 
= 7,3850 
log  sec  5 = 98.0 
2e 
= 9,4811 
c,  = 62.5 
log  c, 
= 1,7959 
log  a — 3,6141963.4 
- 
--  - - - 
log  [2] 
= 4,6287 
a = 4113",356 
2 a 
= 7,3850 
2b 
= 9,8434 
%iV^a)'cl"=  1,4912311.7 
logX  ""  = 3,6924972.9 
log  C2 
= 1,8571 
log  cos  = 9,7405680.1  
log  [3] 
= 4,6163 
— = —71.96  “ 
2d 
= 6,8853 
H“  C3  =r  +31.74 
+ Cj;  =T  — 26 
log  C3 
= 1,5016 
log  S sin  = 4,9242924.2 
log  [5] 
= 2,933 
log  sin  A,^  ' =9,8451111.8 
2d 
= 6,885 
log  S = 5,0791812.4 
log  cos  2 (\i 
= 9,596, 
log  Cr, 
= 9,414^^^ 
log  R^^^^arcV=z  1,4903485.0 
— _ 
logi3  = 3,4426331.0  =d 
log  [4] 
= 4,6234 
log  cos  J X = 9,9999690.4 
2a 
= 7,3850 
+ c^  30.87 
2e 
= 9,4811 
, A-  = — 26 
log  e^ 
= 1,4895 
log  S cos  = 4,9329537.0 
log  cos  A, ^ =9,8537724.6 
log  S = 5,0791812.4 
log  s sin  =.  4,9242924.2 
log  S cos  = 4,9329537.0 
log  tg  A^^  = 9,9913387.2 
