On the Electrostatic Deflection in a Cathode Bay Tube. 25 
Then— 
= CDTi + 3 log 1 + /3 - 1 + /S - J logM + - 3-57 X 6-37 D, 
and — 
"^y^ = cDrnF^ log - 1 +^ - 1 log^ r+ ^1^ - 41-53 x 12-22 d. 
The total deflection is given by — 
nw"^ ^ mv' -^y^) = - 217-2 CD - 529-8 D, 
^\ 60-SX. 
e ^ 
The values obtained by the different integrations are in sufficiently good 
agreement. 
(6) Uniform Field. 
If we had neglected the irregularities of the field and considered the ray 
to enter between the plates parallel to x, the deflection would have been 
given by— 
mv2 ^ ^ _ 3.95^2(3.25 ^ 1.97) X, 
e ' 
= - 48-3 X, 
which differs greatly from that given by the complete solution. 
