KiRSTiNB Smith 
23 
The fraction containing e's equals 
(2g + 2j5 - 1)2 - (2g - 1) (2g + 4:j? - 1) ^ 
(2^ + 4s - 5) {2q + 2p- 1) - {2q + 2s - 3) {2q + 2s + 2p~3) {s - 1) {p - s + 1) ' 
q a 
hence _v_i±^^ _ (_ . 
As 
.+1 Ai. = 1)^ = (- 1)^ {p-i . 2''-2 ^p-2f(p-l)f. 2'"--i» Hi, , 
we therefore find 
^+1 Ass = iSf„ {P-i . 2^-2 _ 2)2 - l)f . 2'' <f-i' n,,3 , 
agreeing with (25). 
a 1 
(6) To evaluate j,+i^s,v+i shall in (26) put A = j,+iA, s = 1, s'=s and 
s" = 2? + 1. Reversing the fractions we then get 
g g q Q Q 
D +l As, _ Ag^ • v+i Ai, ^, s, y+] ~^ Ap-i-x, p+i, 1, s • As, si, v+1 
v+i All Ai, 1, s, s • j)+i Ai, 1, — p+i Aj, J, s, 3,+! 
.(29). 
3 9 
A<? A — A 
jj+l '-*s, s, j)+l, 3)+l aj'-^ss) 
g g+2 g+1 
»+i Ai, 1, s, = j)As-i, J) = (— l)''^''' j)A],5_j^, 
g g+i 
q 3+1 
p+1 As, s, 1, p+1 = (~ l)*j)As-i, S ' 
g 3+2 
J>+1 A], 1, S, S ~ 3)As-l, S-t ' 
g 3 
J)+l Al, 1, 2)+l, V+1 = 3) Al, 1 , 
the right side of (29) can be evaluated by (25). 
We thus get 
q q+l 3+1 g 3+2 
1>+1 As, 3)+l (~ ^Y^^~^ S-1 ■ .9 -Z • ■l-l ( 8)11-3,5 -1 • tXIs, P H~ ^n- gg . p) 
q ~ g+2 q q+l 
Pp-l,s-2 s-1 • p^l,l ~ p^h^-l) 
(30). 
3 
We want here to express the TI's of the numerator by p+iU.^j,^-^ and those of 
3 
the denominator by p+itli,i and we find the following relations 
3 3+1 C,.(7, 
