^s iSjj which muitlply by all numbers fucceffively'; and divide by 
.•28,till you find the Remainder required. Thus twice 285 is 570, 
which divided by 2 Sjthe remainder is 10: Alfo thrice 285 is 85$^ 
>which divided by 28, the reiRainder is 15. Thus if you try on 
^fucceUivelyj you'l findj that iy times 285, which is 4845 ^is the 
Number required, the which divided by 283 the Remainder is an 
Hence then we ftali find, that 
:42oo>is equal to the Solid or Produfl of S285 15, 10. 
6916^ 3)28, 19, 13. 
More eafie wayes of performing ihisfoflulatnm.^xt to be found 
mjFnn Schootens Mi[cellamesj and Tacquef's hrithmetick^ which 
iperchance are not fo obvious to every underftanding. 
'For llluftratioa of the Mk prppofed take this Exam- 
fntheyear ^J'^f'^fi' ^JMeMul? 4845 ? 1211^ 
Indtctio 6y^^ 069i6i 4149^. 
TheSum of the Produds 22p82i5the 
^hich divided by 7980, the remainder is 6381, for the Year of 
xht^nlim Period'^ from which fubftrading 709, there remains 
5572, for the Age of the World ^ according to Arch-Bifhop 
Ujher. 
For DEMONSTRATION of this i^»/^we thus ar- 
gue : 
J. Each MuUiflin Multiflyed by its Remainder y is meajHred 
<?r divided by its own Divijor , having fuch a Remainder as 
is frppojed. 
For before, each Multiplier was defined to be a Multiplex of 
its own Divifor , plus an Vnit. Wherefore Multiplying it by 
^ny Remainder, it doth onely render it a greater Multiplex in 
the faid Divifor 5 plus zn Unity Multiplyed by the Remainder; 
'^which is no other, than the Remainder itsfelf 5 but if o remaine, 
jhat Produdk is deftroyed. 
2, The Sum of the Products y divided by each refpellive Divifor ^ 
^ es the Remainder af signed, 
^iFoi* concerning the firflProdu^l, it is by thc firft Seiiion mca- 
fur<f 
