( 26s ) 
In tbe/jc//» Triangle, GDE, to find GE. 
TheAngleGDE=i28'.9'.3o". 
Toifes. Feet. 
Hence GE 3^897- 
So then,the Line of Diftance between M^hcyfm and Smdo^ be- 
ing divided into three parts, viz. EG, GI, IN, the part EG is al- 
ready found* 
In the [eve nth Triangle FGH^ to find GH. 
r FGH=39°-5i'- o\ 
Angles/ FHG=9i.4<^- 20, 
?HFG=48. 22. 30. 
T. F. 
The Side FG 12963. 3. 
Hence GH 9695- o. 
In the eighth Triangle GHI, to find GI, IH. 
\:GHI=55°.58'.o". 
Angles SGIH=27. 
ClGH=96. 48.0. 
T. 
TheSideGH 9695- 
Hence GI i7557- 
HI 2i®37- 
Thus the Second part of the Three, viz» GI, is found. 
In the ninth Triangle HIK, to find IK. 
CHIK=65^46'- o". 
Angles <HKI=8g. 59.4^- 
CKHI=33- M- 2^0. 
T. 
The Side HI 2 1043. 
Hence IK 11 678. 
In the tenth Triangle IKL, to find KL, IL. 
Angles ^jjjL=5«- 3i- 
^ T. F, 
The Side IK 11683. o. 
Hence KL 11 188. 2. 
IL 1 1 186. 4. 
In 
