i6q Mr, Ivory on cl new Method of deducing 
In order to ^et unothcr eejuntion to compnre with this Isst, I 
resume the equation of the supposition, p = 0*350, 2nd correct 
it by taking in all the terms of the final equation : then 
— ~ X 1*001434, = — 0 002385: 
and now by comparing the two errors I finally get p = 0*35439. 
This value being substituted, the result is as follows, viz. 
r* = 0*994580 
0*932205 
V = 0*933200 
6^ =z= 0*060385 
a' = 3-853570 . . . log. 0-5858633 
log. a = 0*2929316 
4.6* 
6® — ~ X 1*001434= + 0*000002. 
Having now obtained the exact values of p, V and 
it remains to deduce the elements of the orbit from them.. 
Now we have (No. 10) 
= cos. (p <p = 75° 29' 43" 
^ = — cos. i|/ 4/ = 97 25 50 
Anomaly u = 21 56 7 
= cos. (p‘ *.* <p' = 90* 14' 25" 
— ^ — cos. ip' *.* 4^'= 82 34 10 
Anomaly u' = 7 40 15. 
For the perihelion distance, we have 
D = r cos." ~ *.* log. D = 9*9828083 
D =:= r'cos." — *.• log. D = 9*9828083 
D = 0*961188. 
