74 
The author’s analyses of these five bodies led to the 
following formulae - 
A C 62 H 39 N0 8 
B C 52 H 35 N0 8 
C C 2s H u N0 4 
B C 56 H 24 ]Sr 2 O 10 
E C 28 H n N0 6 
The author attaches no importance to these formulae except 
in so far as they furnish a means of explaining the mode in 
which these bodies are formed. It will be seen that they all 
contain the elements of indigo blue, alcohol and acetic acid 
in various proportions. Taking as an instance the body C, 
which is the simplest in constitution, it is apparent that it 
has been formed by the union of 1 atom of indigo blue, 
1 atom of alcohol, and 2 atoms of acetic acid, 8 atoms of 
water being at the same time eliminated, since 
C 28 H n N0 4 + 8HO - C 1S H 5 N0 2 + C 4 H 6 0 2 + 2C 4 H 4 0 4 . 
In like manner E originates from the combination of 2 atoms 
of indigo blue, 1 atom of alcohol, and 5 atoms of alcohol, for 
2(C 28 H u N0 6 ) + 14HO - 2(C 16 H 5 N0 2 ) + C 4 H 6 0 2 + 5C 4 H 4 0 4 . 
The formation of B will be easily understood by a glance at 
the following equation : 
C 52 H 35 N0 8 + 18HO = C 16 H,N0 2 + 6{C 4 HA) + 3(C 4 H 4 0 4 ). 
In the case of A, which is the most complex of all, it is 
necessary to assume that carbonic acid comes into play, since 
C 62 H 39 N0 8 -1- 26HO = C 16 H 5 N0 2 + 8(C 4 H 6 0 2 ) + 3(C 4 H 4 0 4 ) + 2CO* 
It is difficult to say whence this carbonic acid is derived, 
