Is a E> 5 which mtsitiply by all num bers fuccelfively, ■and divide by 
28, till you find the Remainder required. Thus twice 285 is 57c. 
which divided by 2 8, the remainder is 10 :Alfo thrice 285 is 85 
which divided by 28, the remainder is 15. Thus if you try on 
fucceffively, youl find, that 17 times 285, which is 4845,15 the 
Number required, the which divided by 28, the Remainder is an 
Unit. Hence then we fliall find, that 
484s? 1 7 . 
4200/is equal to theSolidorProdudof p8, 15, 10. 
6916 J Jh8, 19. 15, 
More eafie wayes of performing this poftuUttm,aie to be found 
in Van.Schootens Mifccllanies, and Tacquefs Arithmetic^ which 
perchance are not fo obvious to every undemanding. 
For Illustration of the Rule propofed , take this Exam*. 
166$. 
Produ&s. 
121125, 
67200* 
JM9j\ 
22982 i,the 
which divided by 7980, the remainder is 6381, for the Year of 
thefulian Period $ from which fubftrading 709, there remains 
5672, for the Age of the World , according to Arch-Bifhop 
Cyclus Solis 25 ?phe Mul ? 4?45 
CjdmLHM i ^hiplyers. Cf°° 
indict to 63 * 1 3 6916 
The Sum of the Produds- 
tijher. 
For D E M O N $ T R A T ION of this Rule we thus ar- 
lw ® 
U Each Multiplier Multiplyed hy its Remainder, ismeajured 
or divided by its own Divijor , leaving fucb a Remainder 5 as 
is propofed. 
For before, each Multiplier was denned to be a Multiplex of 
its own Divifor, plus an Vnit. Wherefore Multiplying it by 
any Remainder, it doth onely render it a greater Multiplex in 
the faid Divifor , plus an Unity Multiplyed by the Remainder; 
which is no other, than the Remainder its felf 5 but if o remaine, 
that Produd is deftroyed. 
2. The Sum of the Produffs, divided hy each refpeffive Divifor^ 
leaves the Remainder df signed. 
For concerning the firft Produd, it is by the fird Seffion mea- 
" furd 
