*99 
the Stability of Ships . 
from the section 12, ~ f x 536000, by the Rule in. =a 402000 
Sum of the products between section 12 and 4 = 739253 
*’The contents of the volume between the keel and 
the ordinate 1, multiplied into the distance of its 
centre of gravity from the section 12 - = 19465 
Sum of the products arising from multiplying each 
horizontal evanescent solid into its distance from 
the water-section = 1160718 
The sum of products, thus found, divided by the entire vo- 
lume displaced, will be the distance of the centre of gravity of 
that volume from the water-section, or 
DE = “7^- = 9-722 4 feet. 
If the distance between the centres of gravity G and E 
should be assumed i of the breadth BA at the water-line, or 
5.39 feet, this distance being subtracted from 9.22 feet, will 
be the distance of the vessel's centre of gravity beneath the 
water-section, or DG = 3.83 feet. 
To determine the limiting point or metacentre W, above 
which if the centre of gravity G should be raised the vessel 
will overset, it is only necessary to compute, by means of the 
Rule 11. or hi. the value of the line EW 
Fluent of BA 3 x » 
~V 
where z represents any portion of the longer axis : AB = the 
breadth of the water-section, at the distance % from the initial 
point where the mensuration commences : z = a small incre- 
ment of z : V = the solid contents of the volume displaced. 
By computing the cubes of each ordinate of the water-section, 
drawn at the common interval of 5 feet, as represented in the 
* Equal to the sum of the products arising from multiplying each thin horizontal 
segment between the section i and the keel, into its distance from the water-section. 
Qq 3 
