goo Mr. Atwood’s Disquisition on 
table* of ordinates, the total sum of these cubes is = 276573.21 
Cube of the 1st ordinate, or 10.78 = 1252.73 
Cube of the 34th ordinate, or 12.95 = 2171.75 
Sum S = 3424.48 
Sum of the cubes of the 4th, 7th, 
10th, &c. 28th, and 31st = P = 88628.41 
S + P = 92052.89 
Sum of the cubes of the 2d, 3d, 5th, 6th, &c. 32d, 
33 d = Q - - - = 184520.32 
S + 2P + 3Q = 734242.26, this sum x 15, 
will be = fluent of BA 3 x z = 11,013,633.9 ; and 
since V== 119384.0, EW =t= 11 ' 013,633 ' 9 ' = 7.688 feet. 
In this vessel, the centre of the immersed volume E is 9.72 
feet beneath the water’s surface; it follows, that the meta- 
centre will be 2.03 feet beneath the water’s surface. 
The total weight of a vessel and contents is inferred from 
knowing the volume of water displaced by the vessel, the solid 
contents of which space have been calculated in the preceding 
pages, from the areas of the 1 2 horizontal sections intersecting 
the vertical axis at a common interval of 2 feet. By similar 
calculations, we may determine the several weights of tonnage 
which will cause the vessel to sink to any different depths, esti- 
mated by the horizontal line or section which is coincident 
with the water’s surface* 
The solid contents of the volume included between the ho- 
rizontal sections 12 and 9, is found, by the Rule in. to be 39120 
cubic feet ; displacing a weight of water (allowing 35 feet to 
* See Appendix. 
