Supponendo poi 
h 
v 
si ebbe 
log.R' cos.S' = 9.6575678 (— ) 
log.R' sen.5' = 9.9572403 (h-) 
Sezione IL 
k = 66.° 11/20." 72 
log.tang.I = 0.4755421 
/3° = 53.° 26/ 51." 61 
log.a°= 6.3386852 
log.6 =3.5936212 (— ) 
log.c = 3.6343150 (— ) 
log.d =3.6528871 (— ) 
Sezione III. 
log.f = 0.7675319 
log.fe= 3.7103421 
log.Mj = 9.8230720 
log-M/ss 9.5369089 
— 1049 — 
= f — kA log-fe = 7.7605761 
al'- &A' 
= t " — &A" 
log. Ti "= 9.2770477 
log.r/ = 9.5144089 
Iog.T t = 9.1387459 
log.N' — 9.7676758 
log.N =9.6303186 
<»' = 64.° 1 / 14. "93 
5'= 116. 38. 12. 32 
