( 94 ) 
This being done, the firft: pulling of the Operator 
up and down will produce i in the Window, and 7 
in the Subftraffion-Rtng under rhe Index, and the 
Number 1 which remained before in the Syftem C C 
will be changed into 0. Now as 7 is more than 3, 
you muft work on accordingly 5 having done it 
twice more, you will find that there remains under 
a 
the Index jy but 1, (which is the Numerator of your 
Fradton) and below in the two Windows the Quo- 
tient 13. When you confider that 'Divijion is no- 
thing elfe but a repeated Subtraction, you will alto 
eafily underftand the reafon of this Operation. 
Thofe that underftand the matter ever fo little, may 
now eafily conceive how they are to proceed with 
this Machine in larger Examples : However, for 
greater Clearnefs, I will explain it by two Exarnples. 
Suppofing there are fix 
Syftems, a , b , c, d> e> f ; f 
Let all the Numbers point- j 
cd to by the Indexes ww be 
in A B :> thofe which are to < 
be pointed to by the Deter- 
minators, in C D ; and thofe 
which are feen in the Win- 
dows, inEF. Firft of all, 
you rnufl: turn all your Addition-Rings 
Silver-Rlatesan&yomMtiltiplication-Tlates to 0 ; 
1 liz. that under all the Indexes ww, and in the 
Windows nothing may appear but 0. Write the Num- 
ber 3563 near the Determinator, in the Syftems a,b, 
c, d y and dired them accordingly : The other Num- 
ber 58, you muftwrite down likewife, but under the 
Windows in Syftem a and b , as you fee in this 
Scheme. 
5 
of 
8 
D 
the 
