C 5 *7 3 
it appear from the Principles of common Geometry , 
that the moft advantageous Angle for thefe Rhombus's 
is indeed, on that Account alfo, the fame which 
refults from the fuppofed Equality of the Three plane 
Angles that form the above-mentioned folid ones'. 
Let G N and N M reprefent any Two 
adjoining Sides of the Hexagon, that is, Jgi'/nda 
the Section of the Cell perpendicular to 
its Length. The Sides of the Cell are not complete 
Parallelograms as CGN K , BMNK , but Trapezia 
CG NE, B M NE, to which a Rhombus CEBe, 
i? fitted at E, and that has the oppofite Point e in the 
Apex of the Figure, fo that Three Rhombus’s of this 
kind, with Six Trapezia , may complete the Figure of 
the Cell. Let O be the Centre of the Hexagon, of 
which CK and KB are adjoining Sides j join CB 
and KO, interfering it in Ah and, becaufe CO B is 
equal to CKB, and KE equal to 0 e, the Solid 
EBC K is equal to the Solid e BCO-, from which it is 
obvious, that the Solid Content of the Cell will be 
the fame, where-ever the Point E is taken in the 
Right Line K N, the Points C, K, B, G , N, and M, 
being given. We are therefore to inquire where 
the Point E is to be taken in KN, fo that th z Area 
of the Rhombus CEBe , together with that of the 
Two Trapezia CG NE, EN MB, may form the 
Lead: Superficies. Becaufe Ee is perpendicular to 
BC in A, the Area of the Rhombus is A ExBC, 
that of th e Trapezia CG N E, E N MB, is 
CG-\-ENxKC‘, thefe, added to the Rhombus , 
amount to AEy BC+iKNx KC — KExKC ; 
and becaufe 2 K NxKC is invariable, we are to 
E e e e 2 in- 
