[ 5 6 1 ] 
Example r. 
Let the latitudes, on the fame fide of the equa- 
tor, be io° and do 0 } then the middle latitude and 
its complement are 35° and 55 0 , and half the diffe- 
rence of the latitudes is 2 5 ° : and the difference of 
longitude being no°, the operation will ftand as 
below. 
Log. 66 oo' (in 1 io°) . . 3.8 1 95*439 
Conftant log. . . . — 4.101 5105 
- — 1. 9210544 
Log. fin. 35 0 . : . — 1.7587913 
S == . . . . — 1.6796457 
Again T = 1.4281480 
m = .4513202 
Log. T+ 7 «(= 1.8794682) 0.2740350 
Loo-. T — m (= 0.9768278) — 1.9898180 
Log. 0.2842170=0=; — 1.4536500 
g — D (= log. tangent 59 0 1 6') . . . . = 0.2259957 
agreeing to a minute with the folution by a table of meridional 
parts. 
Example 2. 
The reft remaining, let the difference of longitude 
be only 40°; then 
Log. 2400' (in 40°) . . 3.3802112 
Conftant log. . . . — 4.1015^05* 
— 1.48x7217 
Log. fin. 35 0 . . . — 1.7585913 
S = . . . . — 1.2403 130 
D (as before) = — 1.4536500 
S — D (=log. tang. 31 0 27' x) . — 1.7866630 
Vol. 50, 4 C Example 
