C 412 ] 
rule, 
IS n + 1 X 
E 
into 
the 
difference 
between 
P+i 
P+2 
P+i 
p+2 
X 
-qX 
and 
X 
— 
q x — 
12 x 11 
p+i 
P +2 
p+ 
r 
p + 2 
" 77 ” 
r Tr i ii 
~ 
«. 1 
TT 
X 12 
■ — 12I 
— 
10 
— 
10 1 = 
.07699 
1 1 
12 
1 1 
1 2 
&c. There would therefore be an odds of about 923 
1076, or nearly 12 to 1 agctin/l his being right. Had 
he gueffed only in general that there were lefs than 
9 blanks to a prize, there would have been a proba- 
bility of his being right equal to .6589, or the odds 
of 65 to 34. 
Again, iuppofe that he has heard 20 blanks drawn 
and 2 prizes ; what chance will he have for being 
right if he makes the fame guefs ? 
Here X and x being the fame, we have n = 22, 
p — 20, q — 2, E — 23 1 , and the required chance 
~P +7 J+2 V+3 
equal to « + 1 x E x X -yX-j-yxy-ixX 
p + i p + 2 2 p + 3 
P+l p + 2 P + 3 
- — * — qx -|-yxy-iXtf =.10843800. 
p + i ’p + 2 2 p + 3 
He will, therefore, have a better chance for being 
right than in the former inftance, the odds againft 
him now being 892 to 108 or about 9 to 1. But 
fhould he only guefs in general, as before, that there 
were lefs than 9 blanks to a prize, his chance for be- 
ing right will be worfe j for inftead of .6589 or an 
odds of near two to one, it will be .584, or an odds 
of 584 to 415. 
Suppofe, 
