[ 102 ] 
therefore d — i -j-28 — 9 = 25; and 
e -j- 1 = E = 14, therefore e — 13. 
D and E are the cyclar numbers, and 
d and e are the anno dornini numbers fuited to 
the theorem. 
Here then arxd — e 4 d = 28x2x7 4 20 
r= 412 ; and 412 4 532 4 532 4 532 = 2008. 
7 he firft anfvver, therefore, A. D. 412, is too little, 
and when encreafed by three dionyfian periods, or 
multiples of 28 and 19 is too big, going beyond 
the century required. So, when this filar cycle is 1, 
it will not do. 
Let D — 7, the reft as before. Then d 4 9 
— 28 — 7 ; therefore d — 26. Here then 
ra x d — e d ~ 2b X 2 X 13 4- 26 — 754 ; 
and 754 4- 532 4- 532 = 1818. So A. D. 1818 
WILL ANSWER THE QUESTION. 
Let D = 18, the reft as before. Then d 4- 9 
— 28 = 1 1 j therefore d = 37. Here ra x ( 7 ~- — e 
-' r d = 28 X 2 X 24 4- 37 = 1381 j and 1381 4 
532 = 1913. This goes beyond the century re- 
quired ; fo will not do. 
Let D = 24, the reft as before. Then d 4- 9 
= 24 ; th erefore d = 15. Here rtf X^ — e -\ -d = 
28x2x2-415 = 12 7; 127 4- 532 x 4 = 2255 ; 
which goes beyond the century required. 
So there is but one year in the 19th century, viz, 
1818, that will have the conditions required. The 
cycle of the fun will then be 7 ; the cycle of the moon 
14; and the Sunday letter D* and Eajler Day the 
i zd of March 
N. 13 . For 
