I 476 1 
PROBLEM II. 
'Having the hypotenufe ac and one of the angles a, to find 
the bafe ab. 
Let AC=jS, BAC-cf, and fuppofe AB=|6-f,then cof. a = 
b B Z B X vf. f Z B X vf. ^ 
.cot. ACxtang. AB, or.J=->c j-p + — ^ = l--+— p — 
■'Whence z~BbXi — a-\ — xvf. 'C—\ hn. 2 (3 x vf. a -f tang. |3 x vf. 
EXAMPLE. 
Let A=23° 28^ 15", and ac= io° o' o". 
Sine 2 AC 20° o' 9.5340 
Verfed fine a 8.9177 
8.4517 
Log. 2. 0.3010 
f nearly 48' 39'' line 8.1507 
Corredlion + 6 
^ 48 45 and Bc = i 59° 1 1' 1 5'^ 
By this problem, the right afcenlion of any point of 
the ecliptic, whofe obliquity and longitude are known, 
may he found. 
PRO- 
