[ 4^2 ] 
PROBLEM V. 
Suppqfing the fame things given ^ to find either of the angles^ 
as for infiance c oppofite the fide ar. 
We have cot.c=cot. b x cof.BC— lin.Bc x cot. ab x cofec. b 
. Let a be an anrfe whofe cot. - = cot. (S x 
BED r O M r-' 
^ f. tnD — V 1 
lin. 0^-a X cofec. — , and luppofe c = ju + c, then 
Kd—bhx> 
Whence z=mx + 
BD 
m z w. vf. ^ haT> — Ad 
cot C = i + 
M M 
M-* 
ED 
BD 
^x vf. f=lin. ^ X hn. « X cot. J'x tang, y^+cot. ^ x vf. f. 
EXAMPLE. 
Let AB=94° 36^ 58 
Bc=23 28 54 
B~24 54 24 Cotang. 0.333177a 
DifF. AB and BC=7 1 8 34 Sine 9.9760412 
Cofecant AB 0.0014080 
|a= 26 3 44 Got. 10.3166262 
Sin. ^ 
9.286 
Sin. BB 
9.600 
Cot. AB 
8.909 
Tang, j B 
9.344 
f=4' 44'' line 
7.139, this fnbtradled from ^ leaves the 
angle 0=25° 
59' Q'' 
This 
