69 a Mr. hutton’s Calculations to afcertain 
At A 
Theodolite 
n: 4 ft. 10 in. 
At F 
Theodolite 
z= 4 ft. 8f in. 
0 / 
0 / 
0 / 
0 > 
DAB 
31 is 
GFW 
17 27 
W O 58 D 
DAN 
77 3 ° 
N 12 22E 
C-FK 
7 6 7 i 
K 9 50 E 
DAO 
102 361 
O O 58 E 
GFN 
i°3 57l 
N 17 42|E 
DAR 
134 3 J i 
GFD 
172 54 
D 3 37 E 
NAC 
83 13I 
N- 12 20E 
HFG 
IO 9 
G I 36 D 
NAO 
25 4 
HFP 
60 41 
P 5 9 E 
OAS 
27 24 
s 5 25 D 
HFK 
65 58 
K 9 41 E 
OAR 
3 1 55 
R 6 3 ID 
HFN 
93 49 
N 17 35|E 
At B 
DBN 
81 8 
At G 
Theodolite 
— 4 ft. 6| in. 
DBO 
101 41 
DGF 
6 8 
DBA 
i 39 59 
NGD 
59 4i 
At C 
Theodolite 
= 4 ft- 7l in- 
NGF 
6 5 49 
ACD 
126 6 
NGH 
101 9 
ACF 
93 34 
HGF 
166 57 
ACG 
92 15 
HGD 
160 49 
ACH 
85 31! 
HGX 
7 i nf 
ACN 
49 10 
N ID 4E 
HGW 
4 32 
ACB 
8 n 
PGF 
95 5 6 
F I 1-5 E 
At D 
Theodolite 
— 4 ft. 8§ in. 
PGN 
30 6| 
N l6 54 E 
top of Cairn. 
ADC 
48 7 
PGK 
Q 9? 
k 10 15 E 
ADB 
8 45 
PGL 
62 57 
L 0 32 D 
ADN 
49 >4 
n 10 40E 
PGW 
63 20 
w 0 54 d 
ADW 
83 561 
n 10 39E 
PGH 
71 2 
H 3 0 D 
ADH 
88 56 
A I I5E 
p 5 46 E 
ADG 
95 5 
G 3 I7D 
top of ball. I 
ADF 
96 3 
F 3 34D 
1 
