IN PHYSICAL ASTRONOMY. 
273 
(2 — 3 m 4- c) s {r„-4^}-r.-«a^{j-* + £_ + l}=0 
'•''"""-Ik'O 
(*-4.).r u -, 1 .-«=r^{ # -! is +l} 
4r 19 -r 19 = 0 
The equation for determining z may be integrated in the same way. 
- g 2 2 146 + 3 r 0 + z 146 + ~ ^ 3 = 0 
F a i 
Z 147 2 ~* + 2 147 — 0 
— {2(1 — m) -gj%n7- ^ 
— { 2 (1 - m) + g j 2 hs + ^ + 2 =« = 0 
f I* ,3 . 3 ,3m ( a 3 n 
-\ C - g \ z H9 + ¥ r 6 + Zl49 - T2l46 + 2 --, = ° 
r , 1 2 .9 , ,3 m ( a 3 n 
-{c + g| 2 150 + Y ^ + 2 i3o+ 2- z h 6 + --3-° 
— {2(1 — m) — c - g j z 147 + 3 | — ^ - -§-} + 2 1 5 1 + -|- 2147 =l 
— 1 2 ( 1 — m)— c + g j z 148 + 3 {~^f + Y} + z > 32 + 4 2,48 = ° 
— |2 (l — m) + C— 2 149 + 3 - y } + z >53 + \ Z W = 0 
— |2(1— m)+C+g| 2 150 + 3||-J- 1 + £} + 2 154+ y 2 148 = ° 
f \ 2 3 . 3 a 3 n 
- {“-»} z, “ + T s + “27 57 * = 0 
3 m, a 3 q 
Z 15S + ~n T b + 2 156 + o 3 
2 2 /x a , 3 
- {™ +g j 
f 1 2 3 
— <2(1 — m — z li3 — — r a +z lbl — 0 
— |2 (1 — m) — m + g j z 154 + A r 6 + z 158 = 0 
- |2(1 -m) +m-g | “z 1S5 - A r 7 + z 159 = 0 
2 n 2 
