àlaflg. 8 
— 196 — 
1) 
pg' — eo =74.2mm. 
pg' — eo" =63.6 î 
<j^ eo.pg'.eo" = 
31" 0' 10" 
<L eo".eo.pg' = 
58" 59' 50" 
eo — eo" = 
38.21 mm. 
2) 
gn — br =74 mm. 
br-br' =65.3 > 
<[; gn.br.br' = 
28" 3' 47" 
< br.gn.br' = 
61" 56' 13" 
gn — br' = 
34.81 mm. 
3) 
gb — eo =56.5 mm. 
gb — eo' =56.4 > 
<L eo.gb.eo' = 
3" 24' 33" 
<L gb.eo'.eo = 
86" 35' 27" 
eo — eo' = 
3.36 mm. 
4) 
<L op.br. op' = 
9" 44' 10" 
br — op' =47.9 » 
<L br.op-op' = 
80" 15' 50" 
op — op' = 
8.10 mm. 
5) 
<j^ gn.na.na' = 
6" 57' 11" 
na — na' =40.5 > 
<1:1 na.gn.na' = 
83» 02' 49" 
gn = na' = 
4.94 mm. 
6) 
<11 pg' ho. ho' = 
43» 8' 10" 
ho — ho' =24.3 3> 
<41 ho.pg'.ho' = 
46» 51' 50" 
pg'— ho' = 
22.77 mm. 
1) 
zy — zy' =44.8 mm. 
zy — zy"r=44.5 > 
< zy.zy.zy' = 
6» 38' 4" 
< 7.y.zy.zy* = 
83» 21' 56" 
zy— 7<y' = 
5.17 mm. 
Le premier exemple suffira pour la démonstration de l’opératron 
du calcul. 
56 
( a) cos(eo.gb.Eo')= 7 r^ÿ, log cos (eo.gb.Eo')=log. 56— log. 56.9 1 
I O O • : I 
log. 56 =1.7481880, ' ! 
I log. 56.9=1.7551123. cos (eo.gb.Eo')=10"12'lV j 
(log. cos. (eo.gb.Eo')=9. 9930757 — 10. | 
j fj) < eo.Eo'.gb=90"— 10“ 12' 15"= 79" 47' 4 5" | 
I Y) eo— Eo'=v '56.9^ — 5 6^ = v4237.61— 3136 = y/ 101.'6l] 
V 101.61=VJog.l01.61,log.l01.61=2.0069365 f 
V^log.lOl. 61=1.00346825/ 
log. eo— Eo'=1.00346825 \ 
eo — Eo'=10,08 mm. J 
