EEV. T. P. KIEKMAJS" ON THE K-PAETITIONS OE THE E-GON AND E-ACE. 268 
LXIX. It may be useful to collect into one view all our formulas for R"*(r, 
I'”(r, k). 
Problem b. To find k)^ (n>2), we have in XXIV., XXVIII., 
r=:n .. + 
k'^^71 ~\~^2 “f" • • ~1~ ^ n—2A 'jj 
which is always to be understood in Avhat follows), for the equations of condition. 
r—n and k ai-e both multiples of 47i. 
D(2+fl!„ ejx .. xD/2 + (l n— 2 h ») €n— 2 h \=A«-2A, 
\ 4/t f 
k) and 
(A.) 
Here 
^)=0=E; {r,k\-, 
■v>~agdi( J. /3r + n 3k — 2% 
Problem c. To find k)^ (XXIX., XXX.}, 
k'=^n-\-2}iz^ -f- 4/i^^j -j“^2 ~l~ • • “P J 
H=2„{2E’”“^(4+2«„, £o)-f E^-“^-^‘(4+2ao, £„)}, 
E^“^"‘(r, k\, (7>0); 
RrV 
•^aedi 
(r,k)„=^B..A,)-nr^‘^‘(r,k)„. 
Problem d. To find k), (XXXII., XXXIII.), 
T'=-7i -i-4/?^(Zi -|-(Z2”t" . . -}~<z»— -f” 21i{2ccn ^ 
k'^n^ 2A-i-4/h^j -\-€2 “p • • “p 6n-ih\ -f- 2/i . sn | 
M=2^E'”-’”Y3+2a„, sA, 
V 4* 4h) 
/{:)„= spiA^j- 2, k%, (7>0), 
E-“^‘^'(r, >?:)„= 0, 
-r. /2r 2k— n 
Ri (r, -i:).= 2„R“~(-,^- 
—agdi 
R.. (r, 4 ).= 2 MA,- 2 .II’ 
/2r 2k — n\ 
I, mo I 1 
y 7i’ n J' 
(A'.) 
(A".) 
