OF THE EOOTS OF AN EQUATION. 
495 
lY(a). 
4 
13 
o- 
U2 
U 
II 
e 
dd 
(p 
h^c 
(4) 
+ 1 
(31) 
+ 1 
+ 4 
+ 1 
+ 2 
+ 6 
(2F9 
+ 1 
+ 2 
+ 5 
+ 12 
( 1 ^) 
+1 
+ 4 
+ 6 
+ 12 
+ 24 
IVib). 
4 
13 
22 
U2 
U 
= 
e 
hd 
IPc 
(4) 
— 4 
+ 4 
+ 2 
— 4 
+ 1 
(31) 
+ 4 
— 1 
-2 
+ 1 
(2^) 
+ 2 
C> 
+ 1 
(2U) 
— 4 
+ 1 
(10 
+ 1 
V(a). 
V(i). 
o 
14 
23 
U3 
12^ 
U2 
U 
5 
14 
23 
1-3 
12- 
F2 
0 
II 
/ 
be 
cd 
Wd 
h<? 
b^c 
6® 
= 
/ 
be 
cd 
bH 
hc^ 
b^c 
6’ 
(5) 
— 1 
(5) 
— 5 
+ 5 
+ 5 
— 5 
-5 
+ 5 
— 1 
(41) 
— 1 
— 5 
(41) 
+ 5 
— 1 
-5 
+ 1 
+ 3 
— 1 
(32) 
— 1 
— 3 
— 10 
(32) 
+ 5 
— 5 
+ 1 
+ 2 
— 1 
(310 
— 1 
— 2 
- 7 
- 20 
(310 
-5 
+ 1 
+ 2 
— 1 
(2^) 
— 1 
— 2 
— 5 
— 12 
- 30 
(2n) 
— 5 
+ 3 
- 1 
(210 
—1 
— 3 
- 7 
— 12 
-27 
- 60 
(210 
+ 5 
— 1 
(10 
— 1 
—5 
— 10 
—20 
-30 
-60 
— 120 
(10 
— 1 
VI(a). 
6 
15 
24 
l-’4 
3= 
123 
U3 
23 
1-2= 1 
r'2 
U 
II 
d 
¥ 
ce 
b^e 
(P 
bed 
Pd 
6=c= 1 
Pc 
P 
(6) 
i 
+ 1 
(51) 
1 + 1 
+ 6 
(42) 
+ 1 1 
+ 4 
+ 15 
(30 
+ 1 
+ 2 1 
+ 6 
+ 20 
(410 
+ 1 
+ 2 1 
+ 9 
+ 30 
(321) 
+ 1 
+ 3 
+ 3 
+ 8 1 
+ 22 
+ 60 
(20 
+ 1 
+ 3 
+ 6 
+ 6 
+ 15 1 
+ 36 
+ 90 
(310 
+ 1 
+ 3 
+ 10 
+ 6 
+ 18 1 
+ 48 
+ 120 
(2A0 
+ 1 
+ 2 
+ 2 
+ 8 
+ 18 
+ 15 
+ 34 1 
+ 78 
+ 180 
(210 
+ 1 
-4- 4 
+ 9 
+ 6 
+ 22 
+ 
00 
+ 36 
+ 78 1 
+ 168 
+ 360 
(10 
+ 1 
+ 6 
+ 15 
+ 30 
+ 20 
+ 60 
+ 120 
+ 90 
+ 180 1 
+ 360 
+ 720 
6 
9 
15 
¥ 
24 
ce 
P4 
b“C 
3= 
123 
bed 
U3 
Pd 
2= 
1=2= 
PP 
V2 
Pc 
U 
P 
(6) 
- 6 
+ 6 
+ 6 
-6 
+ 3 
-12 
+ 6 
-2 
+ 9 
-6 
+ 1 
(51) 
+ 6 
— 1 
-6 
+ 1 
— 3 
+ 7 
— 1 
+ 2 
-4 
+ 1 1 
(42) 
+ 6 
-6 
+ 2 
+ 2 
— 3 
+ 4 
-2 
-2 
+ 1 
1 
(30 
+ 3 
—3 
-3 
+ 3 
+ 3 
— 3 
+ 1 
1 
(410 
- 6 
+ 1 
+ 2 
— 1 
+ 3 
— 3 
+ 1 
1 
(321) 
-12 
+ 7 
+ 4 
— 3 
— 3 
+ 1 
(20 
— 2 
+ 2 
-2 
+ 1 
1 
(310 
+ 6 
— 1 
-2 
+ 1 
1 
(2=10 
+ 9 
— 4 
+ 1 
i 
(210 
- 6 
+ 1 
1 
(10 
+ 1 
