STEINER’S EXTENSION OF MALFATTl’S PROBLEM. 
267 
we have (p=0, s—0. The equations at the conclusion of the preceding section 
become 
— (^[(/+2^%/^)I+\/9!J+/^]— + C)-s/BC{(\/9i — 2^)1— + 
{(/+2«ya)s+v/Si+y^}*-Sf{(5-o“+!f}=o, 
which may also be written 
(\/33C+4r)(H-0^‘( — C+A\/^d-2^\/33C)(j?+2^|) 
— ;|=y(g+«7i)(AW®)7i®'((ya-2y)5-/»+yao=o- 
{/(5+O+7a(»+20?)}»-6c{g-O«+»“}=O. 
Or observing that 
-+tf^/B=^(^/SC+4r)(^/al+®) ; A+<)v/$'=g(\/M+4f)(v/ac+®) 
and putting for a moment 
>.=^{yac+®)(x/al+®)yicl, 
and therefore 
^ (g+^\/B)(/i+^\/C)\/BC=(\/33C+4r)?i, 
the first equation divides by (x/BC+jT), and the result is 
(H-(f) + ^(>?H- 2 ^|)— ^(l+Q —/*(;? + 2 ^ 1 )} = 0 . 
And by an easy transformation the second equation becomes 
Or putting 
5 +?+«(>i+ 2 «S )=0 
:^(v/a( 5 + 0 -/(?+ 2 i) 5 ))=<i> 
f ='^', 
the equations become 
Whence eliminating O, 
0~2?.O=O 
_ ( 1 ) 2+ { 0 - ( 1 + T } = 0 . 
or observing that 
/ © y / _l+^\ 
V l+flV “(l+5^)^\ 4X2/ 
i+«'=ir*(\/) 3 C+ 4 r)(x/ca+ig)(N/aB+®), 
