772 
AECHDEACON PEATT OIST THE DEELECTIOX 
Putting the numerical values in these formulae, we obtain 
A=17-175, yi+^=17-204, B=l-011; 
and the final results are as follows 
Attraction on A=0’000155/ g~ tan (32 )g. 
Hence the Deflection of the plumb-line =32", or, in the direction of the meiicUan, 
= 32" COS 30°=27"-7 30° being about the azimuth of the Ime along which the whole 
attraction on A acts (see my former Paper). This deflection very nearly coincides rrith 
the deflection calculated in this Paper, which gives a further testimony tha^t the actua 
mass, in reference to its eifect on A, is fairly represented by our- geometacal figure. 
The last formula gives, Attraction of tabular mass on the same base og.. 
That this may be the same as the attraction of the geometrical figme, we must have 
0-0001663 ^=0-0001557, or ^=0-996 mile. 
But I have already shown that the average height of the geometrical figme is one mile, 
and is therefore almost exactly the same as this deduced from attraction. Hence t e 
principle of determining the average height in this manner, in the case of a mass formed 
like the Himmalayas and the Mountain region beyond, is correct; and I sha piocee 
to use it to determine the average height more precisely. ^ rn r -i 
26. If all the numbers in the five columns which appertain to Station A in the iabie 
of Heights (page 750) were replaced by 1000, and the process were gone through by which 
the first column (that for A) in the Table of page 753 is formed, we should have the 
meridian deflection caused by a tabular mass standing on the enclosed space and lOOU 
feet in height above the level of A. This process leads to the following result. As the 
five numbers in each line of the Table from left to right are to be multiphed by the 
same five numbers, viz. by 0-1852, 0-2688, 0-2241, 0-1294, 0-0161, we may add up the 
columns first and then afterwards multiply the aggregates by these constants. 
The aggregates are . 
Multiply these by . . • 
The products are . . • 
The same reduced to miles 
The grand total =5-104 m 
This is the meridian deflection at A caused by a mass 1000 feet high. 
Hence the average height of the whole mass 
_27"-978x feet =0-911 mile. 
5''-814 
And the volume of the whole mass =area of Enclosed Space X average height 
=2,650,000 X 0-911 =2,323,050 cubic miles. 
Also the mass, taking the density § equal to half the mean density of the earth, 
3 2,323,050 - - ^ 
27,000 
32,000 
36,000 
40,000 
32,000 
feet. 
0-1852 
0-2588 
0-2241 
0-1294 
0-0151 
5000-4 
8281-6 
8067-6 
5176-0 
483-2 
feet. 
0-947 
1-568 
1-617 
0-980 
0-092 
mile. 
, and multiplied by 1 
"•1392 = 
5"-814. 
■gn 64,000,000,000 
X Mass of the Earth = 230,8 95^^^ '£‘-<xvth. 
