OBSERVATIONS FOR FINDING THE DENSITY OF PS. 
843 
100 parts =0*3108 grain. 
PS+X. 
T-l-C+0*68gr.+Y. 
PS+Y. 
T+C+0*67gr.+X. 
15*50 
16*55 
21*10 
19*30 
15*90 
15*20 
D= 13*5 
18*70 
16*40 
13*70 
14*30 
C= 13*55 
17*20 
16*00 
14*95 
14*10 
F= 752*4 
16*50 
18*90 
18*00 
15*90 
E= 14*1 
17*15 
14*80 
13*90 
14*90 
17*15 
15*30 
91-95 
90*95 
107*70 
100*70 
6 (PS + X):C!:6(T+C + 0*68 gr.4- Y)+ 1 part. 6(PS + Y)£h6(T + C + 0*67 gr. + X) + 7 parts. 
12 PS:0:12(T + C) + 8*12486 grains. 
32PS£b32(T-t-C) + 21*64665 grains. 
PS^T+C + 0*67646 grain in air (^= 13*45, 5=750*09). 
T=5759'47143 grains. C=1239'88708 grains. PS ^ 2 = 7000‘03495 grains in air. 
For PS, log A=1'32545. For T-l-C+0’676 grain, log A= 1‘32566, Hence t;PS= 
330'86, t;(T+C + 0'676 gr.) = 330’70. Therefore t;PS is larger thant;(T-l-C+0’676 gr.) 
by the volume of 0T6 grain of water, or of 0’00019 grain of air. Hence 
PS=7000‘03516 grains. 
Weighing of PS in water. 
April 1, 1845, 
PS and hook in water. In r 
■ight-hand pan. 
B. 
C. 
F. E. 
gr- 
Scale. 
9*05 
7*85 
769*8 8*1 
1*00 
14*5 
1*08 
20*0 
9 
1*08 
22*0 
8*95 
8*33 
769*65 8*5 
1*00 
13*1 
1*08 
24*0 
8*9 
1*04 
19*5 
8*87 
8*4 
1*08 
27*2 
1*00 
12*0 
8*85 
1*04 
19*0 
• 
1*04 • 
18*5 
8*94 
8*19 
769*72 8*3 
1*044 
18*98 
Counterpoise in air 
(C = 8*19,F= 
769 * 4 , E=8*3) balances PS and hook in 
. water (B = 8 * 94 ) -f 1*0462 grain in air. 
In right-hand pan. 
gr. 
Scale. 
T + F+K + N + R + (l6) + (4) + l*10 
20*67 
-1-1*10 
20*7 
1*10 
20*68 
Counterpoise balances T + F+K + N+R + (1 6) + (4) + 1*0987 grain in air. 
PS and h.in w. (B= 
= 8*94)£i: T+ F + K + N + R + (16) + (4) + 0*0525 grain in air(C = 8*19, F= 
769-72, E=8*3). 
PS and hook in water. In right-hand pan. 
B. 
C. 
F. E. 
gr- 
Scale. 
13*05 
8*85 
762*25 9*6 
1*00 
27-4 
0*90 
9-5 
0*98 
21*9 
12*85 
8*93 
0*96 
19-0 
12*5 
0*94 
18*0 
MDCCCLVI. 
5 S 
