THE CHEMICAL CONSTITUTION OF NAECOTINE. 
665 
I. and II. were of the same preparation, III., IV., Y. were each of different prepa- 
rations. 
For reasons which will be clear from what follows, we have called the base methyl- 
nornarcotine. When freshly precipitated it forms an almost white amorphous powder, 
insoluble in water and ether, slightly soluble in alcohol, and easily soluble in carbonate 
of sodium, by which means it may be separated from narcotine. 
None of its salts form crystalline compounds (the chloride, sulphate, and nitrate have 
been tried). 
On determining the amount of chlorine and sulphuric acid in the chloride and sul- 
phate, the following results were obtained : — 
1-731 grm. chloride gave 0-594 grm. chloride of silver. 
Calculated. Found. 
Chlorine per cent. 
C 20 H ]9 NO 7 , HC1 . . . 8-42 8-48. 
0-4235 grm. sulphate gave 0-1132 grm. sulphate of barium. 
Calculated. Found. 
H 2 S0 4 per cent. 
2(C 20 H 19 NO 7 )SO 4 . . 11-31 11-22. 
The chloride was prepared as follows : the base was dissolved in strong hydrochloric 
acid and fractionally precipitated by water, the middle portion collected, washed with 
dilute hydrochloric acid, and dried over sulphuric acid and lime, before drying it in the 
water-bath. 
The chloride must not be washed with pure water, as it converts it immediately into a 
sticky mass. 
The sulphate was precipitated by dissolving the base in sulphuric acid (one part acid, 
three parts water) and pouring the solution into water, collecting the precipitated sul- 
phate and washing with water, redissolving the precipitate in hot water, and collecting 
the sulphate as it separates out in different portions. Like the chloride it must be first 
dried over sulphuric acid, and then in a water-bath. 
It may be as well to mention that in the further prosecution of this research, one 
of us has already obtained two more bases from narcotine. The one by digesting it for 
a short time with hydrochloric acid, and the other as indicated in our former paper 
(p. 303), by the action of hydriodic acid on it. The reactions may be written — 
I. C 22 H 23 N0 7 +H C1=C 21 h 21 N0 7 +CH 3 Cl. 
II. C 22 H 23 N0 7 +2H C1=C 20 H 19 N0 7 +2CH 3 Cl. 
III. C 22 H 23 N0 7 +3HI =C 19 H 17 N0 7 + 3CH 3 I. 
The preparations and properties of two of these bases (I., III.) will form the subject 
of a future communication. 
