OF ELLIPTIC FUNCTIONS. 
401 
Jr 
k 
1 
12 4 
+ 1 
= 0 
12 s 
-4 
12 s 
+ 6 
12 
-4 
12° 
+ ! | 
-4 
+ 8 
-4 
A 4 
P 
P 
k 
i 
12 6 
+ 1 
= 0 
12 5 
-16 
+ 10 
12 4 
+ 15 
12 3 
-20 
12 3 
+ 15 
12 
+ 10 
-16 
12° 
+ 1 
-16 
+ 32 
-16 
P 
P 
P 
P 
k 1 
12 s 
+ 1 
1 • 
12' 
-64 
+ 56 
12 6 
-112 
+ 140 
' 
12 6 
-112 
+ 56 
12 4 
+ 70 
12 s 
+ 56 
| 
— 112 
12 2 
+ 140 
-112 
12 
+ 56 
— 64 
12° 
+ 1 
-64 
-112 
0 
+ 352 
0 
-112 -64 
n= 3 
12=1, we have — 4(£ — 1) 2 =0 
«=5 
12=1, we have — 16(A 2 — 1) 2 =0 
n=7 
12=1, we have 
1 )\AP + 3/e + 1 )(/e 2 + 3& + 4) = 0 
