50 6 Lieut. Col. Lambtqn’s abstract of the results deduced 
jk (4) = m + Q {sin.V 4) — Sin. 4 / (0 } &c. 
m + Q {Sin. 2 /"' — Sin. 4 / 1 ' J 
To apply this formula to the present measurement, it will 
be necessary to have a terrestrial arc to correspond with the 
celestial one of complete degrees, and the first degree deter- 
mined by observation. If we begin with the degree in 
latitude 9 0 34' 44", which is 60472,83 fathoms, as the mean 
degree deduced from an arc of 2 0 50' 10", 54, where the 
fathoms. 
corresponding terrestrial arc, is *- - 173516,75 
The half of which is the distance of the middle 
point of the arc from Patchipolliam, equal - 85758,375 
To which add half the degree south, or - 30236,415 
Their sum is the terrestrial arc between half 
the degree south of the middle point and 
Patchipolliam, - - = 115994,790 
The latitude of whose commencement is 9°4{33",66 
the latitude of the south extremity of an arc of 
complete degrees. 
Now the terrestrial arc between Patchipolliam 
and Namthabad is » - 248188,534 
And between Namthabad and Baumergidda - 178904,700 
Their sum is the terrestrial arc between 9 0 34' 43" 
66 and Baumergidda - - 543088,024 
The latitude of Baumergidda, by adding the arc 
between Namthabad and Baumergidda 
(=s2° 57* 23^,32 ) by 13 stars, to the latitude of 
Namthabad ( 1 5 0 6' o",2 1 ) gives - 1 8°03' 23", 64 
The latitude of Baumergidda, by adding the 
whole arc between Punnse and Baumergidda 
