514 Lieut. Col. Lambton’s abstract of the results deduced 
on the meridian, due to latitude 13 0 34' 44/'; we shall have 
60491 ,46 ; 7=13° 34' 44." Then if m be the degree 
in any other latitude l ; by equation 5, m — • rn\ 
If m have its middle point on the equator, where l = 0, then 
m 
60491,46 
-f- 30. Sin S'l 
,00053345 
60459,2 fathoms. 
By equation 16, p = m . -—-7 = 60459,2 . 
=3 60459,2 x 1,006431 = 60848 fathoms for the degree on 
the equatorial circle. Put A = 57 0 , 2957795 the arc equal 
radius. Then A . p = 57 0 , &c. x 60848 =2= 3486334 = %a; 
and therefore a == 6972668 fathoms ; and consequently 
b (== a . (1 — e) — 6972668 x 9967742 = 6950176 fathoms, 
the length of the polar axis. Now since 6972668 is the 
diameter of the equatorial circle, then 3,14159, &c. multiplied 
by 6972668, gives 21905280 fathoms for the circumference 
of the circumscribing the elliptic meridian. Put d = 1 — 
— h — =, 00644. Then as 1 : 1 — -j” ~~Sic.) : : 21905280, 
the circumference of the circumscribing circle : 21869976 = 
the circumference of the elliptic meridian ; which, divided by 
4, gives 5467494 fathoms for the quadrantal arc of that 
meridian ; and this reduced into inches, and divided by 
10,000000, will give 39.366 inches for the French metre, at 
the temperature of 62°. Now, the metre deduced from the 
measurements of De Lambre and Mechain, and reduced 
from 32 0 to 62°, was 39,371, English inches, which exceeds 
this one by ,005 inches : a quantity too small to affect any 
standard measure : so that the metre as deduced from a 
comparison of all the recent operations, may be considered, 
as to practical: purposes, the same as that which has been 
