AECTIC SEAS. — PAET IV. NOETHUMBEELAND SOUND. 
329 
The value of m, as found from all the observations, is given in the paper, 
Hence we find 
m=0 h 7 m . 
? m = + 3 h 30 m or — 8 h 30 m . 
The signs of the Lunar Tide show that the negative value of i m is the proper one ; 
hence 
? ;-_8 h 30 m (c) 
We have also, from (a) and (b), 
M sin2^=>/(2-223) 2 H-(l-812) 2 =:2-861, 
and, finally, 
M = 3 - 77 inches (d) 
July 4, 5, 6 . . . . 2 /a=49° 30' N. 
— 2842 
tan 
m-i m =~ 61° 27' or +118° 33' 
=— 4 h 6 m or +7 h 54 m , 
?, n = + 4 h 13 m or — 7 h 47 m , ........ (e) 
of which the latter value must be used. 
We have also 
M sin 2/4= v /(L546) 2 +(2-842) 2 =3-235, 
and, finally, 
M=4‘26 inches (f) 
The mean values of i m and M, deduced from the preceding equations, are 
;.=- 8 - 8 ” ( g ) 
M = 4‘00 inches (h) 
The Lunar Diurnal Tide is therefore expressed by the equation 
Lunar Tide = 4 sin 2/4 cos(m+8 h 8 ra ) (i) 
