OF THE SOLID CRUST OF THE EARTH. 
349 
First, m=50. 
Station Kaliana. 
Ji =0-1564, £=2-8409, A+m£=142-202. 
7t 2 =0-02446, £ 2 -2M= 7-1 8208, (A+m£) 2 =20220-84. 
By (7) we have 2r+l=15, r — 7. Hence formula (5) must be used up to the 6th 
zone ; after that formula (6) up to the 17th or last. 
tan p=0-04045 
h + mk 5*75207 
2r + 1 2r + 1 
r. 
tan i p. 
<?■ 
COS Ip. 
2 cos p — cos 3p — cos5p= 
P. 
2 
1-15041 
49 6 
0-65606 
1-31212+0-83867+0 42262 
2-57341 
3 
0-82172 
39 25 
0 77255 
1-54510+0-47332+0-95757 
2-57599 
4 
0 63912 
32 35 
0-84261 
1 -68522+0- 1 3485 + 0-95588 
2-77595 
5 
0-52273 
27 36 
0-88620 
1-77240-0-12533+0-74314 
2-39021 
6 
0-44247 
23 52 
0-91449 
1-82898-0-31565+0-48989 
2 00322 
By (4) and (5) 11= — l+cos£- 
32(2r+l) 2 r(r + l 
°' 07182 , Resultant: 
1920000 
%• 
r. 
Values of R. 
A 
Resultants. 
2 
-0-34394-0-00322-001 197= -0-35913 
o 
74 
-0 0000138 q 
3 
-0-22745-0-00189-000598= -0-23532 
110 
-0-0000135 „ 
4 
- 0- 1 5 739 - 000 1 08 - 0-00359 = -0-16206 
127 
-0 0000107,, 
5 
-0-11380- 000063 - 0-00239 =-0-11682 
137 
-0-0000083,, 
6 
-0-08551 -0 00037 - 000 171 = — 0 08759 
144 
-0-0000066,, 
„ fa\ i> -16-58107 16-58107 0-07362 
By (bj R— ( 2 r+l) 2 (2r+l) 4 r(r+l)‘ 
7 
— 0 07369 — 0-00033 — 0-00131 = -0-07533 
149 
— 0 000005 8 g 
8 
-0-05737 - 0-00020 - 0 00102=— 005859 
113 
-0 0000034 „ 
9 
- 0-04593 -0 000 1 3 - 0 00082 = - 0 04688 
88 
-00000021 „ 
10 
- 003760 -0-00009 - 0 00067 = - 0-03836 
79 
-0 0000016., 
11 
- 0-03134 - 0-00006 - 0-00056 = - 0031 96 
66 
-00000011 „ 
12 
- 002653 - 0-00004 - 000047= - 002704 
56 
-0-0000008 „ 
13 
- 0-02274 - 0 00003 - 000040 =- 0 0231 7 
109 
-00000013,, 
14 
- 001972 - 0-00002 - 0-00035 = -002009 
87 
-0 0000009 „ 
15 
- 0-01 725 - 0-00002 - 0-0003 1 = - 001 758 
79 
-00000007,, 
16 
-0-01523 - 0-00002-0-00027= - 001552 
61 
-0 0000005 „ 
17 
-0-01354 -000001 -0-00024 = -001379 
37 
-0 0000003 „ 
Resultant at Kaliana for tlie Himalayas , . 
— 0-0000714 g 
