CASH—DECEMBER 
- p 
Day 
|] 
Received 
Paid 
I 
1 I 
• 
| 
! 
<- 
• 
-.1 — 
INTEREST. 
To find the Interest on Any Sum, at Any Rate per 
cent., and For Any Length of Time. 1st. Multiply 
the principal by the rate per cent, expressed in hun¬ 
dredths : this will give the interest for one year. 2nd. 
Find the number of days remaining, by consulting the 
caler.dar ; and multiply the principal by as many hun¬ 
dredths as there are days, and for 3 percent., divide 
the product by 120 ; for 4 per cent., divide by 90; for 5 
per cent., divide by 72 ; for 6 per cent., divide by 60 ; 
for 7 per cent., divide by 52; for 8 per cent., divide by 
45; for 9 per cent., divide by 40 ; for 10 per cent., 
divide by 36 ; and for 12 per cent., divide by 30. This 
will give the interest for the days. 3rd. Add the two 
items of interest, and the sum will be the entire interest. 
To Find the Number of Days from any Day of any one 
Month to the same Day of any other Month. v 
From 
Jan. 
• 
rO 
CJ 
£ 
| Mar. 
Apr. 
May 
June 
f- 
■ Aug. 
Sept. 
Oct. 
• 
> 
o 
£ 
* 
CJ 
CD 
To Jan. 
365 
334 
306 
275 
245 
214 
1S4 
153 
122 
92 
61 
31 
Feb. 
31 
365 
337 
306 
276 
245 
215 
184 
153 
123 
92 
62 
Mar. 
59 
28 
365 
334 
304 
273 
243 
212 
181 
151 
120 
90 
Apr. 
90 
59 
31 
365 
335 
304 
274 
243 
212 
182 
isT 
121 
May 
120 
89 
61 
30 
365 
334 
304 
273 
242 
212 
181 
151 
June 
151 
120 
92 
61 
31 
365 
335 
304 
273 
243 
212 
182 
July 
181 
150 
122 
91 
61 
30 
365 
334 
303 
273 
242 
212 
Aug. 
212 
181 
153 
122 
92 
61 
31 
365 
334 
304 
273 
243 
Sept. 
243 
212 
184 
153 
123 
92 
62 
31 
365 
335 
304 
274 
Oct. 
273 
242 
214 
183 
153 
122 
92 
61 
30 
365 
334 
304 
Nov. 
304 
273 
245 
214 
184 
153 
123 
92 
61 
31 
365 
335 
Dec. 
334 
303 
275 
244 
214 
183 
153 
122 
91 
61 
30 
365 
N. B.—In leap year, if the last day of February 
comes between, add one day to the number in the table. 
Example :—How many days from May 10th to 
Sept. 13th? From the above table we get 123 ; add 3 
for difference between 10 and 13, and we get, 126 the 
number of days required. 
