11 
Příklad ad Ia) pro n — 3 (proud třífásový ). 
Budiž dáno E = 100 , tedy e = 70-71 volt. 
tedy 
r 0 = 0-7 r' — 0-1 r x = 2 >2 = 3 r 3 = 9 
Po = 1 p' = 0 p! = 2 (<2 = 2 (>3 = 0, 
?i = 3 <"2=4 ? 3 = 10 vesměs 
Qi = 4 (>2 = 3 p 3 = o v ohmech. 
Najdeme 
B„ = 1-22 
co 0 = 55° 
R' = 0-1 tf, = Vl3 R 2 — ^13 
á = 0 o, = 56° 19' co 2 = 33° 41' 
= 5 tf 2 =3 P 3 = 10 
cSj = 53° 8 ' S> 2 = 36° 52' <5 3 = 0. 
R 2 — 9 
w 3 = 0 
dle (23) A x = 0-12 B, = 0-16 P t = 0-28 
A 2 = — 0-18392 B 2 = 0-07856 P 2 = 0-28 
A 3 = — 0-05 B 3 = — 0-08660 P 3 = 0-10 
A = — 0-11392 B = — 0-15196 P = 0-66 
dle (15) a = — 4-5826 /? = 6-6899; 
<2c = 0-04 
<? 2 = — 0-04 
<?3 = — 0-10 
<3 = - o-io 
dle (16) — 10-4492 /?, = 17-6899 7j = 20-54 = 14-53 ampér 
« 2 = — 19-4080 /J 2 = 9-9129 J 2 = 21-79 i 2 = 15-41 
« 3 = — 4-7893 /J 3 = — 7-5331 J 3 = 8-93 i 3 = 6-31 
<p,= 59° 26' 
<T, = 152° 57' 
<p 3 = 237° 33' 
dle (17) a x = 15-0320 b x = 11 7 01 = 18-63 
« a = — 14-8254 b 2 = 3-2230 7 01 = 15-16 
« 3 = — 0-2066 ň 3 = — 14-2230 7 03 = 14-22 
ile (18) = — 14-6187 /3/= 17-4460 . 7 / = 22-76 
«í' = — 15-2386 |S 2 '= — 25-2230 7 2 ' = 29-46 
= 29-8573 /? 3 '= 7-7770 7 3 ' = 30-85 
% = 13-17 ampér 
* 02 = 10-72 
*03 = 10-05 
* 1 ' = 16-08 ampér 
*V = 20-82 
* 3 ' = 21-81 
Ue (20) napětí síťové e( = 52-38 e 2 = 55-56 e 3 = 56-81 volt 
lapětí ztrávené v generátoru r 01 = 16-08 e 02 = 13-08 c 03 = 12-26 
.. v síti ě x = 1-61 e 2 = 2-08 ě 3 = 2-18 
lle ( 21 ) efekt užitečný W 1 = 422-0 W 2 = 
W = Z W k = 1493 watt 
dekt ztrávený v generátoru W 01 = 121-4 II ' 02 = 
W 0 = £ W 3k = 272-5 watt 
.. „ v síti _ W x _ = 25-9 W 2 = 
W = 2J \V k = 116-8. watt. 
712-5 
w 3 = 
358-5 
80-4 
§ 
II 
70-7 
43-3 
tf 3 = 
47-6 
XIV. 
