( 32 ) 
For in consequence of T=0 the exponent <p — - will now have 
the value -j - ao(P= 1) for (p -f- %*) (— Aft) > q 0 , and for id. 
the value — oo {p = 0). Only when (p -f % 2 ) (— Aft) = q 0 , P can 
have a value between 1 and 0 (the portion ED), as then the 
1 0 
exponent <p - assumes the indefinite value — . 
Q 0 
So in our example, where q 0 = 3200, — Aft = l f 2 , a — 2700, we 
shall find in E, where v — 2b 2 = l / 2 : 
(T == 0) p E — 6400 — 10800 = — 4400, 
whereas we find in D x , where v=zb l = 1: 
(T = 0) p B = 6400 - 2700 = 3700. 
So these are the limiting values to which the pressure in E and 
D approaches when T gets near 0. For T= 9 these values are 
resp. — 3840 and + 3470. 
The fact now that one value is negative, the other positive, so that 
a positive pressure of coexistence is possible, is determined by this, 
that somewhere between I) and E p can become =0, in other 
words that q 9 lies between —— (— Aft) and — (— A ft). In our 
(2ft s ) 2 ftj* 
example this is the case, as 3200 < 5400 and > 1350. 
Aft), so this would be <1350 in our case, also 
Pd is negative, and then a coexistence liquid-solid would only be 
possible for negative pressures — in other words, no solid state 
would appear in this case. 
If, however, j, > Aft), i. e. >5400 in our case, Pg and 
Pd are both positive, and then a solid state is possible for higher 
pressures (also in the triple point). 
We have tacitly assumed in the above that A ft is negative, so 
— Aft positive. If, however, A ft is positive, which case we shall 
treat separately later on, the factor - in the second term of (3) 
. e—f 
passes into — according to (2) and («) (when we namely then put 
1+0 
—j- A ft = g>), and then p will increase from 0 to 1 without minimum, 
if v increases from ft, to oo. 
!t is, however, possible, that in this case p increases so rapidly 
