(m > 
Then the pressure is further determined by the equation of state, 
whereas £ depends on T and q>, i. e. on T and according to 
formula (3) in II. 
{-Lb){ l+£ c ) V.O+ft) , 
- — — * an<1 v c — o c , as follows from 
AS <fi r = 
the above equation for v C} is evidently = 2b X - -- ,we have also: 
3m*— 2n 
-It.<■« 
because 5 = 5,+ £Ab = 1 — 7 2 £. Further with a = 2700 and R=z 2 
becomes: 
(1+ft) (1—Vi^c) 
We further remark (see also Teyler loc. cit.) that for 0 = 0 or 1 
the formulae (14) duly pass into v c = 3b c and RT C = gj'jf ’ as ^ en 
m and n are =1. It is true that for £=1 we find the expression 
8 a 1 
27 • g ^ or but as ^e quantities refer to double molecular 
quantities, a = 4a,, b c = 2b, for 0 = 1, hence again RT C = " • 
Now in order to calculate the exact values of <p c , £ c , and T c from 
(14«) and j (14 6 ) in connection with (3), we may begin with assigning 
to <p an arbitrary value, which lies in the neighbourhood of the 
expected value of y c . With some values of £, which lie likewise in 
the neighbourhood of £ c , we may then calculate the corresponding 
values of m and n, and further those of <p c and T c from (14°) and 
(14 6 ). Then we may determine £ by interpolation in such a way, 
that the calculated value of <p corresponds with the assumed value. 
Then a value of T c also belongs to this (to be found by interpolation). 
Now we examine (from the above tables) what value of 8 corresponds 
with the assumed value of <p for the value of T c determined just 
now (formula (3) in II). In this we shall, of course, have to inter¬ 
polate again. The value of 8 thus found will not at once correspond 
with the value of 8 determined just now; we then repeat the whole 
calculation with another value of (p, till the two values of £ correspond. 
Thus we find e. g. with </> = 2,5: 
i | m | n | / | Tc 1 f i 
y> = 2,5 '£=0,4 1,27 0,0774 0,4838 172,8 5,144 2,251 
(£==0,5 | 1,281 [0,6924 | 0,4916| 174,8 || 5,114 2,557 I 
