( 434 ) 
(36) 
Hr still 
(37) 
current to that of the whole electrolyte, both taken for r = —■ 
. C 9 . We must therefore put = R x and = R 2 in (28). Hence 
(a _EL ( r ~ R *)( R i— r ) 
2*7] ' riRS-RS) ' ' ’ 
The maximum-value of <o is reached for r = 2 
R t +R, 
being a constant. 
This maximum-value is therefore 
_ HI (#,-.«,) 
~ 4 snj ' * ’ * 
and the proportion of the angular velocity of the ions carrying the 
2B.R, 
~'R 1 +R t ’ 
is found to be 
^ = 2^M,-B±^L_ .*.... (38) 
«>m ' R,R,(R t ~R,) I 
or, since I—a.n (R, 1 — R,') X, 
*=2 nK k,'- <*■+*■>• .(39, 
«>H 1 ’ a R,R, (R,-R,y 
If e is the charge of a gram-ion and if each cm® contains n gram- 
ions, we find 
o = *w(* t +* 2 ),.( 40 ) 
so that (39) becomes 
~~ _g 2L Jht. i_ (^ 1 +^ > ) 3 ^4i) 
<»M ~ en k,+k 2 R y R, {R x -Rtf . 
Put R l= z 1,505 em. and # 2 ==1.J6 cm. Take 
= 0,01 
(coefficient of friction of water). 
We have 
« = 9654. 
If the electrolyte consists in a solution of 10 Gr. of KC1 in a Litre* 
" 7460' 
The velocities for K and Cl are * t =0 f d6.l0-» and * a =0,69.10- r 1 
resp. Substituting these values in the equation (41) we find a very 
small value for — (about 7.10“ 13 ). 
Since the angular velocity is so small in this case, the electrolyte 
will acquire nearly the same velocity as the ions carrying the current. 
Unlike what happens in the case of a gas, the ions carrying the 
