IN GASES : HYDROGEN, CARBONIC OXIDE, AND OXYGEN. 
677 
By the two explosions and absorptions a complete analysis of the: mixture is made. 
The second part of the operation not only serves to control the whole, but gives a 
second independent value for the amount of hydrogen and carbonic oxide burnt in the 
first explosion. By subtracting the quantity of hydrogen burnt in the second explo¬ 
sion from the quantity of hydrogen originally measured, a number is obtained which 
should be identical with the quantity of steam formed in the first explosion—if no 
experimental error occurred. In the column under “ li found ” is given the quantity of 
hydrogen burnt in the first explosion as directly determined by the contraction and 
absorption; in the column under “h calculated ” is given the quantity of hydrogen burnt 
in the first explosion as calculated from the quantity originally measured and that 
found in the second explosion. The mean between these two numbers is taken as the 
correct quantity of hydrogen burnt in the first explosion. 
Exactly in the same way the mean between the found and the calculated quantity 
of carbonic oxide burnt is taken as the correct quantity. 
From the numbers given the entire analysis may be calculated out in the following 
way :— 
No. 1 . Composition of mixture. 
Carbonic oxide. 67T0 
Hydrogen. 21 ’91 
Oxygen. ... 11*09 
100*00 
Volumes reduced to 0° C. and 760 millims. 
Cub. centims. 
Volume of mixture taken. 8'25 
,, after explosion. 6’50 
,, ,, absorption. 5*51 
,, „ addition of oxygen . . . 16*14 
,, ,, explosion. 12-40 
„ „ absorption. 7 "8 3 
First contraction =1 "74 = c First absorption = -99=7: 
Second „ =3"74 = c / Second ,, = 4-57 = /c / 
By first explosion and absorption :— 
Oxygen =l(c+/i:) = -908, Hydrogen —§ ^c — 
By second explosion and absorption :— 
Hydrogen =f(o' — 
h_ 
2 
¥ 
•83, 
•97, 
Carbonic oxide = "99 
Carbonic oxide =4"57 
Total hydrogen =1’80, Total carbonic oxide =5‘56 
