748 
MR. R. C. ROWE OjST ABEL’S THEOREM. 
2e,=<x+ —SE, in the first case 
n 
2e 2 =——$E 0 in the second 
n 
(the notation being obvious) 
wherefore 2e—^e'=a + SE : —XE 7 = an integer 
which is the required result. 
List of Errata. 
In Abel’s Memoir the followino’ slighter mistakes should be corrected :— 
Page 184, 11. 12, 13, 
192, 1. 4, 
200, 1. 3, 
207, 1. 9, 
231, 1. 2, 
231, 1. 3, 
233, 
240, 
243, 1. 2, 
252, last line, 
for F read T 
for 6 x x —/3 read (x— (3) v . 
for hy m 
for x y 
for Zj 
for z. 2 
for y 
for s m 
for nS 2 ,7r 
for 
read hy' x \ 
read y'y. 
read z 2 . 
read z 3 . 
read r throughout. 
c> 
read s m throughout. 
read nSo 
read s„ 
P‘ 
255, last line but one, for 2 
1- 
read 2. 
There are besides these the inaccuracies referred to by M. Libri (the editor of the 
paper) as occurring on pp. 226-8. 
These are too numerous to be treated otherwise than by re-writing the pages, which 
has therefore been done ; and they immediately follow. 
“ Alors l’equation (92) donnera les suivantes :— 
/(12)=/(11)-*—A,,*, 
/(10)=/(11) + |-A 3 i , 
/( 9 ) =/( 6 ) -t-Ash 
/(8) =/(6) -f-A/, 
m =/(6) -i-A/, 
/( 5 ) = /( 6 ) +5~'A 7 U , 
m =/(4> -i-A^, 
./(“0 —f{^) 1 A 10 in , 
/(l) =/(4) -1-A U “ 
done A 0 ' = f /(12)=/(11) —2. 
done A^ =| /(10)=/(11)+1. 
done A 3 i; =f /(9) =/(6) — 1. 
done A/ =f /(8) =/(6) — 1. 
done A/ = £ /(7) =/(6) — J. 
done A A =} /(5) =/(6). 
done A 9 ;ii =4. /( 3 ) =/(4) — 1. 
done A 10 iii =0 /(2) =/(4) — 1. 
doncA n iii =l /(l) =/(4) -2. 
