316 Kremers—On the Classification of Carbon-Compounds. 
hydrogen of the hydro-carbons step by step by sulph-hydride 
groups (—S—H)' and splitting off sulphuretted hydrogen wher¬ 
ever two sulph-hydride groups are connected with the same 
carbon atom. 
In an analogous manner the hosts of nitrogen derivatives of 
the paraffin hydro-carbons can be derived. In this case the sub¬ 
stituting radicle is the amido group, (—» derived 
from ammonia, NH 3 . By substituting this group step by step 
in place of the hydrogen atoms of methane the following mono-, 
di-, tri- and tetra-amido substitution products can be derived: 
C 
H 
^H 
n H 
NH.> 
NH 0 
X H 
NH 3 
,^ T H, 
\nh; 
X H 
NH 3 
nh 2 
Upon splitting off ammonia, 
compounds will result: 
NH„ 
the following nitrogen 
^NH 
^NH 
^NH 
C—H 
c-nh 3 
c— nh 3 
lpN UI 
or 
or 
C|=N V —H 
r ^NH 
On account of the tri- and penta- valency of the nitrogen 
atom the number of possible nitrogen derivatives is greater 
than the number of possible oxygen or sulphur derivatives. 
Ethane, the second member of the series of paraffnn hydro¬ 
carbons, will yield the following amido substitution products: 
/NH» 
/NHo 
/NH 2 
/NH 2 
/NH 9 
/NH, 
C-H 
C-H 
C—NHo 
C—NH„ 
c-nh 2 
C—NHo 
C-NH 
\H 
\H 
\H 
\nh 3 
\nii 2 
\nh 3 
\NH 
^H 
^H 
/H 
/H 
/'H 
Vh 
/NH 
C-H 
C-H 
( 
:-h 
C-H 
C-H 
( 
unh 2 
C—HH 
\H 
\H 
\H 
\H 
nNH 2 
^nh 3 
\NH 
/NH 2 
/NH 9 
/NH, 
*C H 
c—nh 2 
C-NH 
\H 
\H 
I^H 
L-h 
/H 
/H 
C-H 
C 
H 
C—NH, 
^NH 3 
\NH, 
\NH 
*Upon splitting off ammonia from symmetric diamido ethane di-methylene imine will 
result: 
CH, V 
I ~> t h+nh 3 . 
CH/ 
CHjiN H , 
CH.NHiH 
