AND ITS APPLICATION TO MR. B. TOWER’S EXPERIMENTS. 
205 
Taking 
A 0 =. 
A 1= 
A 3 = 
A3—- 
a 4 = 
A = 
■1-5351—2'3018x 
3'0723 + 3-0721 x 
l-8647 + l-5360x 
• -8911— -6571x 
■ -3753- *2582x 
•1396+ T343 x 
B 0 = 
Bx= 
b 3 = 
b 3 = 
B,= 
— -012 — 2-304x 
2T43 + 2-286 x 
T139+ -896 x 
— -455- *316 x 
— -146— -097 X 
^=1-3704 or 78° 31' 30' 
it was found by trial that when 
^>0—48 c 
1 
1 
r 
j 
(99) 
( 100 ) 
and Ko was neglected (under the circumstances 1+ was about -OOOSKj), equation (58) 
gave 
x = —-82295 or — sin 55° 22' 40"' 
and equation (G6) gave y . 
x = —-82274 „ — sin 55° 21' 40+ 
( 101 ) 
The difference "00021 being in the same direction and about the magnitude of the 
effect of neglecting K 3 . 
This solution was therefore sufficiently accurate, and adopting the value of <+ — tf) Q 
+ ■=7° 21' 40".(102) 
Equations (99) then became 
A 0 — 
•3587 
B 0 = 
1-912^ 
A 1= 
•5449 
B x = 
2-263 
a 2 = 
■6010 
b 2 = 
•303 
A 3 = 
-•3505 
b 3 =- 
- -195 
> • • • • 
. . (103) 
a 4 =- 
-•0407 
b 4 = 
•066 
a 5 — - 
-‘0291 
Substituting 
the 
values from 
equations (100), (10 
2), and 
(103) in 
equation (67) 
L 
R 
l-2752K 1 c . 
. . (104) 
eC l Uati01 ’ (68> +-4-7546K,.(105) 
