246 
LITTLEHALES. 
SOLUTION. 
On the Index to Plates, plot the altitude 29° 30' on the 
meridian making an angle equal to the true bearing or 
azimuth (74°), with the right-hand bounding meridian, and 
note the number of the circumference and the number of 
the radial which pass through this point. They are cir¬ 
cumference 7\ and radial 12360. Subtract the co-latitude 
(90° — 35° = 55°) expressed in minutes, which is 55° X 60' 
= 3300, from the number of the radial, and find the inter¬ 
section of the radial whose number is the remainder (12360 
— 3300=) 9060 with the above-noted circumference, 7\. 
Read from the graduations of the projection the declination 
of this point and its hour-angle reckoned from the left-hand 
branch of the bounding meridian. They are declination 
28° 40' north and hour-angle 72J° = 4 h 50 m . From the 
hour-angle thus deduced by inspection, we proceed to find 
the unknown star’s right ascension, as follows: 
L. M. T... 6 h 30“ 00 s 
R. A. M. S. 22 22 33 
Cor. G. M. T.. 1 43 
Local sidereal time. 4 54 
Star’s hour-angle. 4 50 
Star’s R. A... 0 h 4“ 
The right ascension and declination of the unknown star, 
as we have now approximately found them by inspection, 
are R. A. — 0 h 4 m and dec, = 28° 40' N. The star is there¬ 
fore aAndromedae, whose tabulated R. A. == 0 h 03 m 16 s and 
dec. = 28° 32' N. 
